Java get current file path

Java get current file path. In the case of Java there isn’t a specific API to get that value, however there are a lot of ways to get the value easily. toURL(). Therefore I wrote three methods, which all use a different way to extract the path from a given URL. getParentFile(). getName(). /stuff/xyz. If the File path of the file object is Canonical then it simply returns the File of the current file object. platform independent way to get current java executable path and Nov 4, 2009 · Select 'Path' under the list of 'System Variables', and press Edit and add C:\Program Files\java\jdk\bin after a semicolon. class), and that using the package name / class name to derive a path is typically bad practice. Your comment given me the real actual path where is the file location. 2. " you can use this to get the directory of the script that's running) Jul 14, 2011 · Use getClass(). home") + File. It returns the abstract file path as a string. Get current path of executed file. Path and java. The toPath method may be used to obtain a Path from the abstract path name represented by a java. Oct 12, 2011 · The correct form is: String directory = System. E. Note that a package / class name ("a. getAbsolutePath(); String currentDir = helper Oct 22, 2012 · I am trying to locate the path of the current running/debugged project programmatically in Java, I looked in Google and what I found was System. Feb 4, 2015 · I am trying to use a relative path to locate an executable file within a Java class instead of hard-coded lines which worked, but using something like: final static String directory = ". getProperty() is used to obtain the system property. path, and May 29, 2020 · Get current path of java file that is running. In this tutorial, we’ll explore different methods to obtain the path to a resource within a Java JAR file. resolve() #Make the path absolute, resolving any symlinks. GUI: On Windows 10 you can find out the path by going to Control Panel > Programs > Java. This is a common day to day problem Jan 8, 2024 · Java applications have a notoriously slow startup and a long warmup time. dir")` to get the current working directory, the directory from where your program was launched. Learn more Explore Teams Mar 12, 2017 · Because that's is the most accurate way to finding the actual path of the file. This article will explain 4 different ways to get the path of current working directory in java or from java code. Mar 4, 2022 · Well, there are many different ways to get a file in Java, but that's the general gist. ext"); InputStream openit = new FileInputStream(myFile); throws a FileNotFoundException though. listFiles(); Jan 12, 2021 · We can use System. ). Jul 12, 2014 · way of getting home directory of current user is . ' '. Basically my problem is with the path, because I know that listing files under a directory in a nutshell is: File folder = new File(path); File[] listOfFiles = folder. separator +"Desktop"; To get the desktop path, we have to add the “/Desktop” string after the property value of user. They are dependent on the current working directory over which you have totally no control from inside the Java code. path"); File jarFile = new File(dir, jar); Thanks everyone! EDIT: Also, if I ever end up with multiple jars in the classpath, I would need something to check that I got the right one. Oct 12, 2023 · Java の getClass() メソッドを用いたカレントディレクトリの取得. id Dec 29, 2018 · I try to write and read to the file in my java project file called Books. toAbsolutePath() method of java. the given file is Paths created by other providers are unlikely to be interoperable with the abstract path names represented by java. Text file unable to be found and read-1. file class has three methods to find the path of a file. File class to read the /src/test/resources Note that this path is relative to the current working directory, The Path interface includes various methods that can be used to obtain information about the path, access elements of the path, convert the path to other forms, or extract portions of a path. absolute() #See @RonKalian answer dir3 = Path(__file__). println("Path of class being invoked: " + path); } } Is there any way to get and print the correct path in filesystem of MyClass. getProperty() also to build Path for specific files. The CRaC (Coordinated Restore at Checkpoint) project from OpenJDK can help improve these issues by creating a checkpoint with an application's peak performance and restoring an instance of the JVM to that point. js file ran (ex. getHomeDirectory() Jan 25, 2022 · Well, this is off the course, but good to know. In the panel that shows up, you can find the path as demonstrated in the screenshot below. This section addresses these Path methods, sometimes called syntactic operations, because they operate Jun 20, 2024 · Resources within a JAR file are typically accessed using a path relative to the root of the JAR file in Java. txt to reference the file, as this is the canonical place where Maven puts resource files after processing (for example, the maven-resources plugin might have done property substitution on abc. I want a java program that reads a user specified filename from the current directory (the same directory where the . getProperty(“user. Dec 17, 2017 · I'm not sure I understand you completely, but if you wish to get the absolute file path provided that you know the relative file name, you can always do this: System. Using java. Before that, let's understand what is a class file. dir"); or this. Get File Paths Using java. properties"). The code is the following Mar 12, 2012 · I want to create a file in a new directory using the relative path. file package and then perform the following steps. Feb 23, 2015 · The reason is that resource files in the resource folder are stored inside a jar. Paths, you can do the following to show what Java thinks is your current path. getPath(System. Working Directory. replaceAll(“^jar:(file:. class" extension that can be executed by JVM. symbols in the path name, default it follow link. File object. +1. May 26, 2010 · URL location = getClass(). The most simple solution can be: Copy a file from resources to the temporary folder and get a path to that temporary file. A Java class file is a file containing Java byte-code and having " . – I found the following commands return the full path of the parent directory of a Python 3 script. Jan 4, 2012 · Use the length() method in the File class. *; public class GetFileLi System. out. The getPath() method belongs to the File class of Java. /var/data/stuff/xyz. I have read this. I didn't get solution of my problem from this post, but this code was what i need for my project. If the path is already absolute then the method returns path else this method resolves this path in an implementation-dependent manner by resolving the path against a Nov 30, 2011 · new File(inputFilePath). getAbsolutePath() shows the correct path. file. Jun 20, 2024 · Resources within a JAR file are typically accessed using a path relative to the root of the JAR file in Java. g. Get file path of a file (NIO Path). Whether other providers make any guarantees is provider specific and therefore unspecified. toRealPath() – Canonical path similar to file. ) uses paths relative to the current user directory (see java. Mar 17, 2024 · The simplest approach uses an instance of the java. – Actually with Java 8 the right way is to use: System. getPath()); String jar = System. Don't fiddle with relative paths in java. You can then just use ClassLoader#getResource() wherein you pass the root-package Jul 30, 2019 · Get the Current Working Directory in Java - The method java. Python 3 Script: #!/usr/bin/env python3 # -*- coding: utf-8 -*- from pathlib import Path #Get the absolute path of a Python3. (getting path of running java application and add the path to java. Jul 30, 2013 · I have made a pure java app which tells me about number of files in a given directory. Here is the code: public &lt Oct 27, 2010 · I am upvoting this. listFiles The above works fine in Windows (accepting current path as, ex: D:/Tomcat/bin), however in Linux, it doesn't work taking current path as user's root, ex: '/' -- However the above works when I execute a standalone java program (below), it just doesn't work in Tomcat's context. System. util. When we compile a java file, we get a class file. As an example, when calling c:\scripts\MyScript. Path, we can use the following APIs to get the file path of a file. You can get the absolute path to your current class executing the code using the following : YourClassName. However, if your file path has other non-alphameric characters such as + you will have problems with URLDecoder mangling your file path. getProperty("java. getLocation(); File file = new File(location. if you run a script with "node . Path used to return a Path object representing the absolute path of this path object. dir2 = Path(). getParent() – Get parent directory of the path. class file is run). My code so far is this: import java. File currentDirFile = new File(". 3. getPath(String) or Paths. Apr 13, 2022 · 3. Your code doesn't work because the FileInputStream(. The dialogue can be quite handy: it allows you to highlight and copy the file path. Sets of class files / packages can be in multiple different class paths, which can be directories or jar files. toAbsolutePath (). They automatically open input/output streams to the specified file in internal memory. Get File Path Using getPath() Method in Java. class. ", "/") + ". Syntax: Within a ServletContextListener class, I want to access the files under the SQL directory and list them. separator + "other"; File. getContextClassLoader())). getAbsolutePath()); In the above program, we used Path's get() method to get the current path of our program. normalize() 方法从当前路径返回一个路径，在这个路径中，所有多余的名称元素都被删除。 Nov 10, 2009 · Selecting from the menu: File -> Properties; Using the shortcut: Alt + Enter; This gives you a dialogue which contains both the full path of the document, as well as the relative path from the workspace root. The system-dependent default name-separator character, represented as a string for convenience. txt. Paths created by other providers are unlikely to be interoperable with the abstract path names represented by java. class file for the class itself is: File[] configFiles = new File( this. This system property is specified by the key which is the parameter for the method. ");` After that I made an inst Is there a way to get the path of main class of the running java program. We use the Path class from the java. Jan 8, 2024 · Java applications have a notoriously slow startup and a long warmup time. If we want to make the result relative to the source directory, we can use the getParent() method: Solution. println("File path: " + new File("Your file name"). This returns a relative path to the working directory. groovy from c:\users\Scott\ I wanted to know c:\scripts\. getAbsolutePath()); The File class has several more methods you might find useful. properties from the current directory. So we first need to get to the parent of the file, its directory and then go to the second file. Given two absolute paths, e. Mar 17, 2024 · Java applications have a notoriously slow startup and a long warmup time. path. "); String helper = currentDirFile. dat so long as the original Path, the URI, and the new Path are all created in (possibly different invocations of) the same Java virtual machine. Why? Sep 15, 2020 · 1. getProperty (“user. dir1 = Path(). So they don't have a real path in the file system. path"); but the problem is, if I run like Aug 24, 2020 · 1. – Jun 27, 2011 · For reference: The accepted answer on the question here is what I was looking for. Apr 12, 2018 · Use File's getParentFile() method and String. toAbsolutePath() – Full file path similar to file. Apr 6, 2011 · I had performance doubts using the Java URL class for just extracting the path from an URL and thought that this is an overkill. The Path methods throws NoSuchFileException if the file is not present May 28, 2020 · Hello, Using java. Path. Mar 18, 2013 · I want to be able to list the files in the current directory. We build a regex and use String‘s replaceAll() method to extract the part we need: String path = url. The java file is compiled using javac command as shown Oct 2, 2010 · If it's already in the classpath, then just obtain it from the classpath instead of from the disk file system. getName(); Jan 31, 2017 · The file specified in java. getURLs() is woefully inadequate if you want your code to be portable today, because numerous runtime environments no longer use java. path -my dll is always in this path-) Thanks. jar is located All of the answers on this topic that make use of the new Java 8 functions are neglecting to close the stream. But note that using the default package is discouraged (the above will work with any package). I want to the server to list the files the client can copy. In other words, if the user specifies the file name to be "myFile. From the javadocs: Returns the length of the file denoted by this abstract pathname. In my case, my path is not begining with drive letter "C:\\". But the file handling is done by the operation system. I tried System. getDefault() . getClass(). If the path was created using Filesystems. File dir = new File(". Once Jan 8, 2024 · Java applications have a notoriously slow startup and a long warmup time. Creating the directory "tmp" is easy enough. Normally, that means to get the path from the root folder to the folder where the program file has been placed. 'C:\Program Files\Java\jdk1. Instead "\home\". Run where java on Command Prompt. This for 7 and on, and uses NIO. Now I set current directory by using the following code: `File f = new File(". ]jar Oct 20, 2014 · I am trying to write a simple tcp client/server app that copies a file. file, which references a file on the disk. getDefault(). structure is. An absolute pathname is complete in that no other information is required in order to locate the file that it denotes. nio. Oct 12, 2023 · 使用 Java 中的 normalize() 方法获取当前工作目录. 6. a file is updated, but this can easily result in two events: One for the updated content and one for updating the last-modified timestamp, happening within a short period of time. File. Overall, the result is correct. println(new File(""). I've thrown together some spaghetti code that will get the current . getLocation(). And if your file path has spaces encoded as %20, this approach may appear to work. logging. Oct 12, 2023 · The java. home"), "downloads", "somefile. The java. /ggla/ Dec 6, 2010 · Now available on Stack Overflow for Teams! AI features where you work: search, IDE, and chat. For example, running the following command java -Djava. All of the answers on this topic that make use of the new Java 8 functions are neglecting to close the stream. home property and get the desktop path in Java: String desktopPath = System. Jun 5, 2020 · Getting the path of current directory is often required when you need to access some files from code generally for reading text or properties files. A pathname, whether abstract or in string form, may be either absolute or relative. io. Jan 13, 2011 · Command line:. home"); and to append path separator. getProperty ("user. Get the location of executables in PATH. The example in the accepted answer should be: I've tried numerous methods now, including FilenameUtils. myFile. txt). toAbsolutePath() – Full file path. The problem is that I can access the file only if partialPath has full path to the file. getResource(""). class files (a/b/C. . or . lang. dir"); When I run this statement For Example from E:\. get() method to get the Feb 2, 2024 · Here’s what each part of the syntax means: public: This method is accessible by any class. dir"); If You are running a . getPath()); // This returns the exact location of the Class in question. Method Invoked Returns in the Solaris OS Returns in Microsoft Windows Comment; toString /home/joe/foo: C:\home\joe\foo: Returns the string representation of the Path. file is not read from the classpath. For java. home"); The bug JDK-6519127 has been fixed and the "Incompatibilities between JDK 8 and JDK 7" section of the release notes states: Using Paths and Path from java. The example in the accepted answer should be: May 8, 2009 · File myFile = new File("localpath. Jun 20, 2022 · It’s a common task in applications to require to interact with files located in a relative path from where the application is executed. file=smclient-logging. replace(". jar” part, convert it back to a URL object, and use the Paths class to get the path as a String. Jan 8, 2024 · As the file URL format on different operating systems may differ, we’ll extract the “file:…. Feb 21, 2012 · The Java properties file format dictates that the backslash character ("\") escapes the character that follow it, so to get a literal windows path you must have:. Furthermore, it’s essential to understand how these paths are structured to retrieve resources effectively. Example 6: Get path of a file in the system download folder Path path1 = FileSystems. The resulting Path can be used to operate on the same file as the java. dat /var/data How can one create a relative path that uses the second path as its base? In the example above, the result should be: . if you do cd /somefolder and then java -jar /otherfolder/file. Instead it is read from the file system relative the current directory. Java cannot determine the root of your project without projects meta data. Dec 9, 2020 · You might assume that you get one event, whenever e. C") is different from the path of the . getAbsolutePath(). Because my production server is linux, while my local development is windows. Using FileSystemView. ' from the path of the File, if presen I spent a while messing around with this problem, because no solution I found actually worked, strangely enough! The working directory is frequently not the directory of the JAR, especially if a JAR (or any program, for that matter) is run from the Start Menu under Windows. I use this statement for this purpose : String currentPath = System. jar file it returns the present working directory, this is the directory where the . toExternalForm() The above works fine for paths, which are not prefixed with file:/, but for paths prefixed with file:/, the . Sep 24, 2019 · An advice of limited use, as it relies on the working directory to be the maven root. , inner classes, etc. My file is location at C:\Users\tester\Documents\Java Project\Samples\ProjectOne\src\pdfReader However when I us Jan 8, 2024 · In our example, we created the Path pointing to a specific file. separator. Use the listFiles() to retrieve an array of File objects for each file in the directory, and then call the getName() method to get the filename. getPath() Jul 23, 2012 · The cleanest way to enumerate the classpath today is to use the ClassGraph library (I am the author). We can use system-specific System. String currentUsersHomeDir = System. config. There are also methods for matching the path string and methods for removing redundancies in a path. properties SMMain will read the smclient-logging. – This quote from the Javadoc might be helpful:. get (the latter is a convenience method for getPath), the method performs minor syntactic cleanup. Path also provides following methods for getting various paths: path. The Canonical File is always absolute and unique, the function removes the '. This allows you to bypass the directory and File objects altogether which is a pretty clean solution. Note that the old answer of reading the java. dir”) to get current working directory path. /. how it would work on your_file_path All current answers fail if eg. Sep 15, 2020 · In Java, we can use `System. path property or calling ((URLClassLoader) (Thread. System. The below program shows different ways like File, Paths, FileSystems, or system property to get the current working directory; all methods will return the same result. Since it returns a Path object, we need to change it to a string using the toString() method. getCodeSource(). This section addresses these Path methods, sometimes called syntactic operations, because they operate Oct 13, 2021 · Getting the current working directory in Java means getting the path of the directory (folder) from where your program has launched. To achieve these steps, you might have methods like the following: /** * Gets the base location of the given class. normalize() from commons IO, but I can't seem to be able to get a resource in another folder to get a Java FXML file. ; static: The getProperty() method belongs to the System class itself rather than an instance of the class. 0. file. And even then, you should rather use target/classes/abc. However, when I create the file, it is just located in the current directory not t Jul 16, 2015 · Hi I need to read the file by using FileInputStream but I didn't get the right path. File documentation). Mark's comment is a better solution thanlastIndexOf():. Update: as per the comments, it's apparently already in the classpath. I've made something that should work but doesn't return all the file names. Now click on 'new' button under system variables and enter 'JAVA_HOME' as variable name and path to jdk home directory (ex. getProtectionDomain(). 0_24' if you are installing java version 6. Learn to find the current working directory for any application using the Java APIs. Jul 16, 2019 · The Java Path interface was added to Java NIO in Java 7. txt"); Happy Learning !! If you're trying to get access to a file, try the openFileOutput() and openFileInput() methods as described here. Apr 19, 2024 · Let’s see an example of how to use the user. Delete the temporary file. See full list on baeldung. To obtain the current working directory, the key used is user. toURI method is converting it to a invalid URI, by appending value of current dir, and hence the path becomes invalid. lastIndexOf() to retrieve just the immediate parent directory. home. An abstract pathname is an object of java. txt")); does not work. Not perfect? This is actually the most reliable since the other proposed suggestions returns the current working directory which is not per se the folder where the JAR is located. "); File[] filesList = dir. getProperty("user. Pass an empty string to the Paths. toRealPath()) – For symbolic links or resolving the . get (). Jan 30, 2019 · The getCanonicalFile() method is a part of File class. Jan 28, 2015 · File dir = new File(YourMainClass. If we want to make the result relative to the source directory, we can use the getParent() method: Feb 2, 2024 · Here’s what each part of the syntax means: public: This method is accessible by any class. I want to get the directory c:\\temp\\java\\ using the File object. Dec 25, 2022 · To find the current working directory for any Java application, we can use System. b. logpath: C:\\Users\\Maurice\\Desktop\\Logs May 20, 2023 · In this article, Let's learn How to Set Destination of the Class File in Java. Working code. parent Sep 15, 2015 · I'm trying to get current path of system. We then change the relative path to an absolute path using toAbsolutePath(). get() method to get the Jan 8, 2024 · In our example, we created the Path pointing to a specific file. The return value is unspecified if this pathname denotes a directory. class file just being invoked? Similarly, if I invoke jar file from java -jar command, is there any way to get a path of jar file from within classes inside that jar? Oct 22, 2012 · Two ways. toURI(). Create a File object, passing the directory path to the constructor. A program that demonstrates this is given as follows −Example Live Dec 17, 2009 · Like this: String path = MyClass. *[. java"; But note that sometimes class names are annotated (e. Solution. 6 and above script. String otherFolder = currentUsersHomeDir + File. D:/ |---Project |-----bin |-----src I want to get the path as D:\Project\bin\. dir. txt", and that file is already in the current directory: reader = new BufferedReader(new FileReader("myFile. By creating a new File object with a relative path and then retrieving the absolute path, you get the current working Jul 24, 2013 · I was confronted with code which tries to read some configuration files from the same directory where the . currentThread(). Java の Object クラスの getClass() メソッドを利用すると、現在実行中のクラスを返すことができ、さらに getPath() メソッドを利用して現在の作業ディレクトリのパスを取得することができます。 The Path interface includes various methods that can be used to obtain information about the path, access elements of the path, convert the path to other forms, or extract portions of a path. This function returns the Canonical File of the given file object. dir”) or Paths. getResourceAsStream("foo. Do tests using a temporary path. I think the problem is: Java knows the current directory with the new setting. com Jul 1, 2010 · If you want to get your current working directory then use the following line. jar then other suggestions would return /somefolder. getCanonicalPath(). uvgwt pjlrec uzvcngo asox sgfkp ktw zas euilz zjzaq dhmym